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Anônimo(a)
Asked: 2011-03-04T03:16:18-03:00

trigonometry identity?

1.{(cot x) / (cot x – cot 3 x)} + {(tan x) / (tan x – tan 3x)} =?

2.if sec^2 x = 3, & 0 < x = 90, calculate
(tan^2 x- cosec^2 x) / (tan^2 x+ cosec^2 x)

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2 Answers

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  1. AntCLeal

    Darling. Dá para transleirar para o pt.

    • 0
  2. Mr Jay

    sec²x = 1+tg²x
    3² = 1 + tg²x
    8 = tg²x
    tgx = 2 sqrt 2

    cossec²x = 1+cotg²x
    cossec²x = 1+(1/2 sqrt2)²
    cossec²x = 1+ 1/4.2
    cossec²x = 1+1/8
    cosec²x = 9/8
    cossecx = 3/2sqrt2
    cossecx = 3sqrt2/4
    2
    (tg²x – cossec²x)/(tg²x + cossec²x)
    8 – 9/8 / 8+9/8
    64/8 – 9/8 / 64/8 + 9/8
    55/8 / 73/8
    55 /73

    1
    1 – (cotgx/ cotg3x) + 1 – (tgx – tg3x)
    Well, this one I don’t know this identity cotg3x.
    However, I thought that we could calcute it by dividing
    cos3x / sen3x = cosx. cos3x – senx. sen3x / senx.cos3x – sen3x.cosx,
    but I cannot see any method to solve something like that!!!

    where tg is the same tan
    cotg is the inverse of tan

    • 0

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